175x^2+120x-16=0

Solution for 175x^2+120x-16=0 equation:

175x^2+120x-16=0

a = 175; b = 120; c = -16;
Δ = b2-4ac
Δ = 1202-4·175·(-16)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-160}{2*175}=\frac{-280}{350}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+160}{2*175}=\frac{40}{350}
=4/35
$